LOG(10,x)^3 - LOG(10,x) = 0
C.E. x>0
Pongo t = LOG(10,x)
t^3 - t = 0---> t·(t + 1)·(t - 1) = 0
t = -1 ∨ t = 1 ∨ t = 0
x = 10^(-1)--> x = 1/10
x = 10^1---> x = 10
Quindi: x = 1/10 ∨ x = 10 ∨ x = 1
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