Thanks
Thanks
log_2 (x) = u con x > 0
log_2 x =/= 1
x =/= 2
log_2 x =/= - 1
x =/= 1/2
3/(u-1) + 2/(u+1) = 2
3(u+1) + 2(u-1) = 2(u^2 - 1)
5u + 1 = 2u^2 - 2
2u^2 - 5u - 3 = 0
2u^2 - 6u + u - 3 = 0
2u(u - 3) + (u - 3) = 0
(u - 3) (2u + 1) = 0
u = 3 => log_2 (x) = 3 => x = 8
u = -1/2 => log_2 (x) = -1/2 => x = 2^(-1/2) = 1/rad(2)