5^(2·x) - 5^(x + 2) - 5^(x + 1) + 125 = 0
5^x = t
t^2 - 25·t - 5·t + 125 = 0
t^2 - 30·t + 125 = 0
(t - 5)·(t - 25) = 0
t = 25 ∨ t = 5
5^x = 5^2----> x = 2
5^x = 5---> x = 1
(x = 2 ∨ x = 1)
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