n!/((n - 3)!·3!) + n!/((n - n + 3)!·(n - 3)!) = 2·n!/((n - 4)!·4!)
n!/((n - 3)!·3!) + n!/(3!·(n - 3)!) = 2·n!/((n - 4)!·4!)
semplificando:
n·(n - 1)·(n - 2)/3 = n·(n - 1)·(n - 2)·(n - 3)/12
1/3 = (n - 3)/12---> n = 7
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