Notifiche
Cancella tutti

[Risolto] Equazione n.3

  

0

6(x/3 + 1) - 20 - 13x = 5[(2x + 4)/6 - x - 8(x/5 + 1/2)]

Autore
2 Risposte



4

6(x/3 + 1) - 20 - 13x = 5[(2x + 4)/6 - x - 8(x/5 + 1/2)]

=================================================

$6\left(\dfrac{x}{3}+1\right) -20-13x = 5\left[\dfrac{2x+4}{6}-x-8\left(\dfrac{x}{5}+\dfrac{1}{2}\right)\right]$

$2x+6-20-13x = 5\left[\dfrac{2x+4}{6}-x-\dfrac{8}{5}x-4\right]$

$-11x-14 = \dfrac{5}{6}(2x+4) -5x -8x-20$

$-11x-14 = \dfrac{5}{3}x +\dfrac{10}{3}-13x-20$

moltiplica tutto per 3:

$-33x -42 = 5x +10 -39x -60$

$-33x-42 = -34x -50$

$-33x +34x = -50+42$

$x = -8$

@gramor 👍👌👍



5
Immagine WhatsApp 2024 05 30 ore 22.15.03 ef1cb093

@marimarilu 👍👌🌻👍



Risposta