6(x/3 + 1) - 20 - 13x = 5[(2x + 4)/6 - x - 8(x/5 + 1/2)]
6(x/3 + 1) - 20 - 13x = 5[(2x + 4)/6 - x - 8(x/5 + 1/2)]
6(x/3 + 1) - 20 - 13x = 5[(2x + 4)/6 - x - 8(x/5 + 1/2)]
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$6\left(\dfrac{x}{3}+1\right) -20-13x = 5\left[\dfrac{2x+4}{6}-x-8\left(\dfrac{x}{5}+\dfrac{1}{2}\right)\right]$
$2x+6-20-13x = 5\left[\dfrac{2x+4}{6}-x-\dfrac{8}{5}x-4\right]$
$-11x-14 = \dfrac{5}{6}(2x+4) -5x -8x-20$
$-11x-14 = \dfrac{5}{3}x +\dfrac{10}{3}-13x-20$
moltiplica tutto per 3:
$-33x -42 = 5x +10 -39x -60$
$-33x-42 = -34x -50$
$-33x +34x = -50+42$
$x = -8$