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[Risolto] Equazione Goniometrica

  

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sin(π/2+x) = -cos(x/3), cos(α) = sin(π/2-α) ---> -cos(x/3) = -sin(π/2-x/3)

sin(π/2+x) = -sin(π/2-x/3)

  • π/2+x = -π/2+x/3 +2kπ

x-x/3 = -π/2-π/2 + 2kπ

2/3x = -π + 2kπ

x = 3/2*(-π + 2kπ) --> x = -3/2*π + 3kπ

  • π/2+x + -π/2+x/3 = π + 2kπ

x+x/3 = π + 2kπ

4/3x = π + 2kπ

x = 3/4*(π + 2kπ)

x = 3/4*π + 3/2*kπ



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