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4

2^(-2x) - 3*2^(-x) - 4 = 0

[2^(-x) - 4)]*[(2^(-x)+1]=0

Legge di annullamento del prodotto 

2^(-x)=2^2

x= - 2

@stefanopescetto ...smart !!👍👍👍

Great job Steve 



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@casio 👍👍



1

* (1/4)^x - 4 = 3*2^(- x) ≡
≡ (1/2^2)^x - 2^2 - 3/2^x = 0 ≡
≡ (1/2^x)^2 - 3/2^x - 2^2 = 0 ≡
≡ u^2 - 3*u - 2^2 = 0 ≡
≡ (u = - 1) oppure (u = 4) ≡
≡ (1/2^x = - 1) oppure (1/2^x = 2^2) ≡
≡ (2^x = - 2^0) oppure (2^x = 1/2^2) ≡
≡ (log(2, 2^x) = log(2, - 2^0)) oppure (log(2, 2^x) = log(2, 1/2^2)) ≡
≡ (x = i*π/ln(2)) oppure (x = - 2)
VERIFICA al link
http://www.wolframalpha.com/input?i=2%5E%28i*%CF%80%2Fln%282%29%29%2C2%5E%28-2%29
CONTROPROVA al link
http://www.wolframalpha.com/input?i=%281%2F4%29%5Ex-4%3D3*2%5E%28-x%29

@exprof ...mi sa che Angela si perde 🤨



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