(4^(2·x) - 1)·(2^(x + 1) - 4^x) = 0
4^(2·x) - 1 = 0
4^(2·x) = 4^0
2·x = 0---> x = 0
2^(x + 1) - 4^x = 0
2^(x + 1) = 2^(2·x)
x + 1 = 2·x---> x = 1
In definitiva: x = 0 ∨ x = 1
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