x^2/α + y^2/β = 1
si ha: α > β
con
α = a^2
β = b^2
γ = c^2 = α - β = 1^2
2^2/α + 0^2/β = 1 passa per [2, 0]
4/α = 1---> α = 4
x^2/4 + y^2/β = 1
4 - β = 1---> β = 3
x^2/4 + y^2/3 = 1
(x^2/4 + y^2/3 = 1)·12
3·x^2 + 4·y^2 = 12
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