(4^x - 5·2^x + 4)/(5^x - 125) ≥ 0
2^x = t---> t^2 - 5·t + 4 = (t - 1)·(t - 4)
(2^x - 2^0)·(2^x - 2^2)≥ 0
x ≤ 0 ∨ x ≥ 2
5^x - 5^3 > 0---> x > 3
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