compiti 2 media

x/3 = y/11 = z/8

x = 3y/11

z = 8y/11

x+y+z = 3y/11+8y/11+y = 176

3y+8y+11y = 176*11

22y = 176*11

y =176*11/22 = 176/2 = 88

x = 8*3 = 24

z = 8*8 = 64 

x/4 = y/5 = z/6

x = 4y/5

z = 6y/5

x+y+z = 4y/5+y+6y/5 = 225

4y+5y+6y = 225*5 

15y = 225*5

y = 225*5/15 = 225/3 = 75 

x = 4y/5 = 75*4/5 = 60

z = 6y/5 = 75*6/5 = 90

x/2 = y/4 = z/5

x = 2y/4

z = 5y/4

x+y+z = 2y/4+y+5y/4 = 33/10

2y+4y+5y = 33*4/10

11y = 33*4/10

y = 3*4/10 = 12/10

x = 2y/4 = y/2 = 6/10

z = 5y/4 = 12*5/(10*4) = 15/10

x/9 = y/10 = z/14

x = 9y/10

z = 14y/10

x+y+z =9y/10+y+14y/10 = 165

9y+10y+14y = 1650

y = 1650/33 = 50 

x = 9y/10 = 9*50/10 = 45

z = 14y/10 = 14*50/10 = 70 

x/6 = y/9 = z/8 

x = 6y/9

z = 8y/9 

x+y+z = 6y/9+y+8y/9 = 115

6y+8y+9y = 115*9

y = 115*9/23 = 45

x = 45*6/9 = 30

z = 45*8/9 = 40 

x/7 = y/20 = z/3

x = 7y/20

z = 3y/20

x+y+z = 7y/20+3y/20+y = 240

7y+3y+20y = 240*20

y = 240*20/30 = 160

x = 160*7/20 = 56

z = 160*3/20 = 24 

2x = 4y/3 = 3z/2

x = 4y/6 = 12y/18

z = 8y/9 = 16y/18

x+y+z = 12y/18+16y/18+y = 23/2

12y+16y+18y = 23*18/2 = 23*9

46y = 23*9 

y = 9/2

x = 4y/6 = 36/12 = 3

z = 8y/9 = 72/18 = 4 

5x/2 = 8y/3 = 4z/5 

x = 16y/15 = 64y/60

z = 40y/12 = 200y/60

x+y+z = 64y/60+200y/60+y = 27/8

8(64y+200y+60) = 27*60

y = (27*60)/(324*8) = 5/8 = 15/24

x = 16*5/(8*15) = 2/3 = 16/24

z = 40*5/(12*8) = 25/12 = 50/24 

verifica : 15/24+16/24+50/24 = 81/24 = 27/8  OK !!

Ciao!

380) Se la somma è 225 con le tre incognite: x,y e z basta fare una proporzione/rapporto, dato che x:4, y:5 e z:6 e, parti dalla somma 225:15=15... NO! devo fare x=60, y=75 e z=90

Se hai dubbi chiedi pure

x = 7y/3 ; z = 4y/3

x+y+z = 7y/3+y+4y/3 = 98

7y+3y+4y = 98*3

y = 98*3/14 = 21

z = 21*4/3 = 28

x = 21*7/3 = 49