[Risolto] Ciao! Mi potreste aiutare a fare questa espressione con le potenze? Grazie mille.

(((16^4/8^5)^17/2^14)^5/4^6 - 2^2)^11/((2^5·2^7)^2/(2^2·2^4))=

=(((2^16/2^15)^17/2^14)^5/2^12 - 2^2)^11/((2^5·2^7)^2/(2^2·2^4))=

=((2^17/2^14)^5/2^12 - 2^2)^11/((2^5·2^7)^2/(2^2·2^4))=

=((2^17/2^14)^5/2^12 - 2^2)^11/((2^12)^2/(2^2·2^4))=

=(2^3 - 2^2)^11/((2^12)^2/(2^2·2^4))=

=(2^3 - 2^2)^11/((2^12)^2/2^6)=

=2^22/((2^12)^2/2^6)=

=2^22/(2^24/2^6)=

=2^22/2^18 = 2^4 = 16

possiamo scrivere le potenze  16^4 = (2^4)^4 = 2^16;  8^5 = (2^3)^5 = 2^15;

in questo modo hanno la stessa base;  2^16 : 2^15 = 2^1;

{[(16^4 : 8^5)^17 : 2^14]^5 : 4^6 - 2^2}^11 : [(2^5 · 2^7)^2 : (2^2 · 2^4)]=

={[(2^16 : 2^15)^17 : 2^14]^5 : 4^6 - 2^2}^11 : [(2^12)^2 : 2^6] =

= {[(2^1)^17 : 2^14]^5 : 4^6 - 2^2}^11 : [2^24 : 2^6] =

= {[2^17 : 2^14]^5 : 4^6 - 2^2}^11 : 2^18 =

= {[2^3]^5 : 4^6 - 2^2}^11 : 2^18 =

= {2^15 : (2^2)^6 - 2^2}^11 : 2^18 =

= {2^15 : 2^12 - 2^2}^11 : 2^18 =

= {2^3 - 2^2}^11 : 2^18 =

= {8 - 4}^11 : 2^18 =

= 4^11 : 2^18 =

= (2^2)^11 : 2^18 = 

 = 2^22 : 2^18 = 

= 2^4 =

= 16.

@lya  ciao.  Metti le foto diritte altrimenti viene il torcicollo. Ciao.