[Risolto] Buonasera ,vi chiedo per favore un aiuto con l'espressione 618

618)

$\frac{1}{5}+\left(1-\frac{4}{3}\right)^2·\left\{\left(1-\frac{11}{5}\right)^2·\left[\left(2-\frac{1}{6}\right)+\left(-\frac{1}{4}-5\right)·\left(\frac{2}{7}-\frac{1}{3}\right)\right]\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\left(\frac{3-4}{3}\right)^2·\left\{\left(\frac{5-11}{5}\right)^2·\left[\left(\frac{12-1}{6}\right)+\left(\frac{-1-20}{4}\right)·\left(\frac{6-7}{21}\right)\right]\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\left(-\frac{1}{3}\right)^2·\left\{\left(-\frac{6}{5}\right)^2·\left[\frac{11}{6}+\left(-\frac{\cancel{21}^1}{4}\right)·\left(-\frac{1}{\cancel{21}_1}\right)\right]\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{9}·\left\{\frac{36}{25}·\left[\frac{11}{6}+\left(-\frac{1}{4}\right)·\left(-\frac{1}{1}\right)\right]\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{9}·\left\{\frac{36}{25}·\left[\frac{11}{6}+\frac{1}{4}\right]\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{9}·\left\{\frac{36}{25}·\left[\frac{22+3}{12}\right]\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{9}·\left\{\frac{\cancel{36}^3}{\cancel{25}_1}·\frac{\cancel{25}^1}{\cancel{12}_1}\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{9}·\left\{\frac{3}{1}·\frac{1}{1}\right\}^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{9}·3^2+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{\cancel9_1}·\cancel9^1+\frac{1}{10}=$

$=\frac{1}{5}+\frac{1}{1}·1+\frac{1}{10}=$

$=\frac{1}{5}+1+\frac{1}{10}=$

$=\frac{2+10+1}{10}=$

$=\dfrac{13}{10}$

l'ho fatta di fretta...

ciao