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Area di base $\small Ab= \dfrac{C×c}{2} = \dfrac{\cancel{16}^8×12}{\cancel2_1} = 8×12 = 96\,cm^2;$
volume $\small V= \dfrac{Ab×h}{3} = \dfrac{\cancel{96}^{32}×17}{\cancel3_1} = 32×17 = 544\,cm^3.$