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Raggio del secondo cerchio:
$r_2= \sqrt{\left(\dfrac{7}{5}\right)^2×\dfrac{A_1}{\pi}} $
$r_2= \sqrt{\left(\dfrac{7}{5}\right)^2×\dfrac{1256}{3,14}} $
$r_2= \dfrac{7}{5}×\sqrt{\dfrac{1256}{3,14}}$
$r_2= \dfrac{7}{5}×\sqrt{400}$
$r_2= \dfrac{7}{5}×20$
$r_2= \dfrac{7}{\cancel5_1}×\cancel{20}^4$
$r_2= 7×4 = 28\,cm.$