Proporzione continua (approssimata al centesimo)
(1/2-15/22:25/11)(14/25:28/15+4/5)
(Il b)
Grazie a chi risolverà la proporzione
Proporzione continua (approssimata al centesimo)
(1/2-15/22:25/11)(14/25:28/15+4/5)
(Il b)
Grazie a chi risolverà la proporzione
(1/2-15/22:25/11)(14/25:28/15+4/5)
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$\big(\frac{1}{2}-\frac{15}{22} : \frac{25}{11}\big) : x = x : \big(\frac{14}{25} : \frac{28}{15}+\frac{4}{5}\big)$
$\big(\frac{1}{2}-\frac{15}{22} × \frac{11}{25}\big) : x = x : \big(\frac{14}{25} × \frac{15}{28}+\frac{4}{5}\big)$
$\big(\frac{1}{2}-\frac{3}{2} × \frac{1}{5}\big) : x = x : \big(\frac{1}{5} × \frac{3}{2}+\frac{4}{5}\big)$
$\big(\frac{1}{2}-\frac{3}{10}\big) : x = x : \big(\frac{3}{10}+\frac{4}{5}\big)$
$\big(\frac{5-3}{10}\big) : x = x : \big(\frac{3+8}{10}\big)$
$\frac{2}{10} : x = x : \frac{11}{10}$
$x^2 = \frac{2}{10} × \frac{11}{10}$
$x^2 = \frac{1}{10} × \frac{11}{5}$
$x^2 = \frac{11}{50}$
$\sqrt{x^2} = \sqrt{\frac{11}{50}}$
$x= \frac{\sqrt{22}}{10}$ → $(≅ 0,469042)$