When a $2.5 \mathrm{~kg}$ mass is placed on top of a vertical spring, the spring compressess by $1.5 \mathrm{~cm}$. Find the force constant of the spring.
$$
[k=1.6 \mathrm{kN} / \mathrm{m}]
$$
When a $2.5 \mathrm{~kg}$ mass is placed on top of a vertical spring, the spring compressess by $1.5 \mathrm{~cm}$. Find the force constant of the spring.
$$
[k=1.6 \mathrm{kN} / \mathrm{m}]
$$
100
punti
Livello 1
=============================================================
Applied mass $m= 2.5\,kg;$
therefore applying Hooke's law:
force acting on spring $F= m·g = 2.5×9.80665\approx{24.517}\,N;$
spring compression $\delta= 1.5\,cm·10^{-2} = 0.015\,m;$
spring constant $k= \dfrac{F}{\delta} = \dfrac{24.517}{0.015} \approx{1634.467}\,N/m\;→\,\approx{1.6\,N/m}.$
54361
punti
Genius I
x = m*g/K
k = m*g/x = 2,5*9,806*10^2/1,5 = 1.634 N/m = 1,63 kN/m
109887
punti
Genius II