Solo esercizio 674 il 673 no
Solo esercizio 674 il 673 no
Esercizio 674.
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$-\big(3ab^2-\frac{1}{2}a\big)+\big[\big(3a-\frac{1}{2}b^2\big)^2+\frac{1}{8}b^4\big]-\big(a+\frac{1}{2}b^2\big)\big(a-\frac{1}{2}b^2\big)-\frac{5}{8}b^4+6ab^2$ =
= $-3ab^2+\frac{1}{2}a+\big[9a^2-3ab^2+\frac{1}{4}b^4+\frac{1}{8}b^4]-\big(a^2-\frac{1}{4}b^4\big)-\frac{5}{8}b^4+6ab^2$ =
= $-3ab^2+\frac{1}{2}a+9a^2-3ab^2+\frac{1}{4}b^4+\frac{1}{8}b^4-a^2+\frac{1}{4}b^4-\frac{5}{8}b^4+6ab^2$ =
= $\frac{1}{2}a+8a^2+\big(\frac{1}{4}b^4+\frac{1}{8}b^4+\frac{1}{4}b^4-\frac{5}{8}b^4\big)$ =
= $\frac{1}{2}a+8a^2+\big(\frac{2+1+2-5}{8}b^4\big)$ =
= $\frac{1}{2}a+8ab^2+\frac{0}{8}b^4$ =
= $8a^2+\frac{1}{2}a$